z^2=-2z-15

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Solution for z^2=-2z-15 equation: 



z^2=-2z-15

We move all terms to the left:

z^2-(-2z-15)=0

We get rid of parentheses

z^2+2z+15=0

a = 1; b = 2; c = +15;
Δ = b2-4ac
Δ = 22-4·1·15
Δ = -56
Delta is less than zero, so there is no solution for the equation

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